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10-12-2016
Physics

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A 4.3 kg bowling ball is initially at rest. If a 15 N force acts on it for 0.85 s, what is the final velocity of the bowling ball?

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11-12-2016

According to Newton's 2nd law of motion, F = ma ==> a = F / m =15/4.3 = 3.48 m/s^2. Now using kinematic equation, v=u+at => v= 0 + 3.48x0.85 => V= 2.958 m/s

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