Answer: 12.48
Step-by-step explanation:
38x38+bxb=40x40
1444+b=1600
1600-1444=156
[tex]\sqrt156[/tex]=12.48
The base of the house is 12.48 foot far from the foot of the ladder.
The Pythagoras theorem states that the square of the longest side must be equal to the sum of the square of the other two sides in a right-angle triangle.
|AC|^2 = |AB|^2 + |BC|^2
It is given that A 40-foot ladder reaches 38 feet up the side of a house.
We need to find that How far from the base of the house is the foot of the ladder.
Using Pythagoras theorem, we get;
[tex]38^2 + b^2 =40^2\\\\1444 + b^2 = 1600\\ \\b^2 = 1600 - 1444 \\\\b^2= 156\\\\b = 12.48[/tex]
Therefore, the base of the house is 12.48 foot far from the foot of the ladder.
Learn more about Pythagoras theorem;
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