A metal cube dissolves in acid such that an edge of the cube decreases by 0.53 mm/min. How fast is the volume of the Cube changing when the edge is 6.3 mm?

Respuesta :

Answer:

The volume of the cube is decreasing at a rate of 63.1071 cubic millimeters per minute.

Step-by-step explanation:

The volume of a cube is given by:

[tex]V=s^3[/tex]

Implicitly differentiate the equation with respect to time t:

[tex]\displaystyle \frac{dV}{dt}=3s^2\frac{ds}{dt}[/tex]

The edge of the cube decreases by 0.53 mm/min. Therefore, ds/dt = -0.53.

When the edge is 6.3 mm, s = 6.3.

Substitute and evaluate:

[tex]\displaystyle \frac{dV}{dt}=3(6.3)^2\left(-0.53\right)=-63.1071\text{ mm}^3/\text{min}[/tex]

The volume of the cube is decreasing at a rate of 63.1071 cubic millimeters per minute.