Answer:
The molecular formula is Fe₂O₃
Explanation:
The molar mass of the compound is 199.55 g/mol; this means that if we have 1 mol of the compound, we'd have 199.55 g, we'd also have:
- 199.55 * 69.96/100 = 139.57 g of iron
- 199.55 * 30.06/100 = 59.98 g of oxygen
Now we calculate the moles of each element present in the given masses, using their atomic masses:
- 139.57 g Fe ÷ 55.84 g/mol = 2.50 mol Fe
- 59.98 g O ÷ 16 g/mol = 3.75 mol O
Then in 1 mol of the compound, there's 2.50 mol Fe and 3.75 mol O:
We convert the coefficients into integers (Divide them by the lowest number among them and multiply them by two):
