Help me please I really need help

Answer:
[tex]17\sqrt{2}[/tex] ft
Step-by-step explanation:
take angle b as reference angle
using sin rule
sin 45 = opposite / hypotenuse
[tex]\frac{1}{\sqrt{2} }[/tex] = 17 / BC
BC =17 / [tex]\frac{1}{\sqrt{2} }[/tex]
BC = 17 * [tex]\sqrt{2}[/tex]
BC = [tex]17\sqrt{2}[/tex] ft
Answer:
BC = 17[tex]\sqrt{2}[/tex] ft
Step-by-step explanation:
Using the sine ratio in the right triangle and the exact value
sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then
sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{BC}[/tex] = [tex]\frac{17}{BC}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )
BC = 17[tex]\sqrt{2}[/tex] ft