Answer:
[tex]{ \tt{question \: 1 : }} \\ 2 {x}^{2} - 4x - 3 = 0 \\ x = 2.58 \: \: and \: \: - 0.58 \\ \\ { \tt{question \: 2 : }} \\ x(x - 2) = 4 \\ x = 4 \: \: and \: \: 6 \\ \\ { \tt{question \: 3 : }} \\ {9x }^{2} + 12x + 4 = 0 \\ (3x + 2)(x - 9) = 0 \\ x = \frac{ - 2}{3} \: \: and \: \: 9 \\ \\ { \tt{question \: 4 : }} \\ {x}^{2} + 2x = 1 \\ {x}^{2} + 2x - 1 = 0 \\ x = 0.41 \: \: and \: \: - 2.41[/tex]
