Answer:
[tex]=0[/tex]
Step-by-step explanation:
Given:
[tex]4x-3(2x-y)[/tex]
Let's substitute for y
[tex]4x-3(2x-4)=0[/tex]
Let's distribute the parenthesis
[tex]4x-6x+12=0[/tex]
Combine like terms
[tex]-2x+12=0[/tex]
Subtract 12 from both sides
[tex]-2x=-12[/tex]
divide both sides by -2
[tex]x=6[/tex]
Now let's insert 6 for the [tex]x[/tex] and 4 for the [tex]y\\[/tex]
[tex]24-3(12-4)=[/tex]
[tex]24-3(8)=[/tex]
[tex]24-24=0[/tex]
Hope this helps
