Respuesta :

Answer:

Max E=3.8 Voltage

Step-by-step explanation:

[tex]maximum-value -of cos(\theta) =1, when \theta=0,360,720\\110\pi t=0, therefore t=0, 1.04, 2.08 etc[/tex]

The maximum voltage for the electric circuit is E = 3.8 when the value of the trigonometric function cos(110π t) has the maximum value = 1, from the range of cosine function.

What is the range of the trigonometric function cosine?

The range of the trigonometric function of cosine, that is, cos θ, is [-1, 1], that is, -1 ≤ cos θ ≤ 1.

How do we solve the given question?

We are given that the voltage E in an electrical circuit is modeled by E = 3.8cos(110π t).

We are asked to find the maximum voltage E that can be obtained from the circuit.

The voltage E = 3.8cos(110π t).

In the given formula 3.8 is constant and cos(110π t) is variable. The value of E is maximum when the trigonometric function cos(110π t) attains the maximum value.

Since its a cos function, the maximum value it can attain = 1, as the range of the trigonometric function of cosine, that is, cos θ, is [-1, 1], that is, -1 ≤ cos θ ≤ 1.

When the variable attains the maximum value = 1, the value of the voltage E  = 3.8*1 = 3.8.

∴ The maximum voltage for the electric circuit is E = 3.8 when the value of the trigonometric function cos(110π t) has the maximum value = 1, from the range of cosine function.

Learn more about the ranges of trigonometric functions at

https://brainly.com/question/9565966

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