There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "
According to Pythagoras theorem,
[tex] \boxed{ \large \boxed{h {}^{2} = {b}^{2} + p{}^{2} }}[/tex]
note :
- p = perpendicular / opposite side
- b = base / adjacent side
- h = hypotenuse
let's solve for " y² " first ( square of other missing side )
[tex]➢ \: \: {y}^{2} = {8}^{2} + 3 {}^{2} [/tex]
[tex]➢ \: \: {y}^{2} = 64 + 9[/tex]
[tex]➢ \: \: {y}^{2} = 73[/tex]
now let's solve for " x " , by using pythagorous theorem
[tex]➢ \: \: {x}^{2} = {y}^{2} + {6}^{2} [/tex]
[tex]➢ \: \: {x}^{2} = 73 + 36[/tex]
[tex]➢ \: \:x {}^{2} = 109[/tex]
[tex]➢ \: \: x = \sqrt{109} [/tex]
Approximate :
[tex]➢ \: \: 10.44 \: \: units[/tex]
[tex] \mathrm{✌TeeNForeveR✌}[/tex]
