Answer:
[tex](x+1)^2+(y+4)^2=97[/tex]
Step-by-step explanation:
Hi there!
Equation of a circle centered at (h,k):
[tex](x-h)^2+(y-k)^2=r^2[/tex] where r is the radius
1) Plug in the center
[tex](x-(-1))^2+(y-(-4))^2=r^2\\(x+1)^2+(y+4)^2=r^2[/tex]
2) Plug in the given point and solve for r²
[tex](x+1)^2+(y+4)^2=r^2[/tex]
Plug in (-5,5)
[tex](-5+1)^2+(5+4)^2=r^2\\(-4)^2+(9)^2=r^2\\16+81=r^2\\r^2=97[/tex]
3) Plug r² back into the equation
[tex](x+1)^2+(y+4)^2=r^2\\(x+1)^2+(y+4)^2=97[/tex]
I hope this helps!
