Answer:
The correct answer is "0.3410, 0.4990".
Step-by-step explanation:
Given values are:
[tex]n=150[/tex]
[tex]p=\frac{63}{150}[/tex]
[tex]=0.42[/tex]
At 95% confidence interval,
C = 95%
z = 1.96
As we know,
⇒ [tex]E=z\sqrt{\frac{p(1-p)}{n} }[/tex]
By substituting the values, we get
[tex]=1.96\sqrt{\frac{0.42\times 0.58}{150} }[/tex]
[tex]=1.96\sqrt{\frac{0.2436}{150} }[/tex]
[tex]=0.0790[/tex]
hence,
The confidence interval will be:
= [tex]p \pm E[/tex]
= [tex]0.42 \pm 0.079[/tex]
= [tex](0.3410,0.4990)[/tex]
