Answer:
[tex]F=48.62N[/tex]
Explanation:
From the question we are told that:
Angle [tex]\theta= 20[/tex]
Mass [tex]m= 20kg[/tex]
Coefficient of kinetic friction [tex]\mu=0.1[/tex]
Generally the equation for Force Required to jeep sled moving is mathematically given by
[tex]F= mg sin \theta - \mu N[/tex]
Where N is normal force
[tex]F_N=Wcos\theta[/tex]
[tex]F_N=20*9.8*cos 20[/tex]
[tex]F_N=184.18N[/tex]
Therefore
[tex]F= (20*9.8) sin 20 - (0.1) (184.18)[/tex]
[tex]F=48.62N[/tex]
