Respuesta :
Answer:
0.601 = 60.1% probability that the weight of a bag will be less than the maximum allowable weight of 50 pounds
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 49.02 pounds and a standard deviation of 3.83 pounds.
This means that [tex]\mu = 49.02, \sigma = 3.83[/tex]
What is the probability that the weight of a bag will be less than the maximum allowable weight of 50 pounds?
This is the p-value of Z when X = 50. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{50 - 49.02}{3.83}[/tex]
[tex]Z = 0.256[/tex]
[tex]Z = 0.256[/tex] has a p-value of 0.601.
0.601 = 60.1% probability that the weight of a bag will be less than the maximum allowable weight of 50 pounds
