Answer: The minimum score a person must have to qualify for the society = 147.4
Step-by-step explanation:
Let X be the test scores.
As per given,
X is normally distributed.
Mean [tex](\mu) = 110[/tex]
[tex]\sigma=5[/tex]
[tex]$\begin{array}{l}\quad P(z>2)=0.07 \\\therefore \quad 1-P(z<2)=0.07 \\\therefore \quad P(2<2)=1-0.07 \\\therefore \quad P(2<2)=0.93 \\\qquad \begin{aligned}P(z<1.48) &=0.93[\text { using } z- \text { -table] } . \\z=1.48 \\\text { let } z &=\frac{x-\mu}{\sigma} \\x &=\mu+2 \sigma \\x &=140+(1.48)(5) \\x &=147.4\end{aligned}\end{array}$[/tex]
The minimum score a person must have to qualify for the society = 147.4
