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An 800-kHz radio signal is detected at a point 4.5 km distant from a transmitter tower. The electric field amplitude of the signal at that point is 0.63 V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. What is the magnetic field amplitude of the signal at that point

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okpalawalter8

Answer:

[tex]B_2=2.1nT[/tex]

Explanation:

From the question we are told that:

Frequency [tex]F=800kHz[/tex]

Distance [tex]d=4.5km[/tex]

Electric field amplitude [tex]B_2=0.63V/m[/tex]

Generally the equation for momentum is mathematically given by

 [tex]B=\frac{E}{C}[/tex]

Therefore

 [tex]B_2=\frac{0.63}{3*10^8}[/tex]

 [tex]B_2=0.21*10^{-8}[/tex]

 [tex]B_2=2.1nT[/tex]

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