Answer:
0.0806 mm
735.588 MPa
Explanation:
Given data:
Esteel = 200 GPa
vsteel = 0.3,
EAI = 70 GPa, vAI = 1/3
diameter of steel ball = 20-mm
Applied force = 1 kN force
density of steel ( ρ ) = 8050 kg/m^3
weight of steel = ρvg = 0.33 N
Calculate the size of
i) contact patch
size of contact patch = [tex]\sqrt[3]{\frac{3FR}{4E} }[/tex] ----------- ( 1 )
where: F = 1000 + 0.33 = 1000.33 N , r = 0.01 m,
E = 57.26 * 10^9 ( calculated value )
Input values into equation 1
size of contact patch ( a ) = 0.0806 mm
ii) maximum contact pressure
P = 3F / 2πa^2
= ( 3 * 1000.33 ) / 2π(0.0806)^2
= 735.588 MPa
