✏️ Development:
✍ Having as t₃ =10 and t₁₀ = -4. We have to find the common ratio.
❑ If, in front of the sequence from 3 to 10, there are 7 numbers, that is, 7 terms, we have to find a pattern, what I used was this one.
[tex]\large {\text {$ \sf 7 \longrightarrow Number \: Terms $}}[/tex]
[tex]\large {\text {$ \sf x \longrightarrow rasion $}}[/tex]
We see that in the calculation, the only number that fits is -2.
➤ Because if we stop to think about it, we have -2 of common ratio among these 7 terms is -14, so 10-14 = -4
So the hypothesis is correct!
➜ Being right as -2 and resuming the terms of 10, we have:
[tex]\huge {\boxed {\blue {\sf t_{10}, t_{11}, {\bf t_{12}} = \{ -4 , -6 , \bf -8 \} } }}[/tex]
So t₁₂ is equal to -8.
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