Respuesta :
Answer:
f(-3) = -12
g(-2) = -19
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Algebra I
- Functions
- Function Notation
Step-by-step explanation:
Step 1: Define
Identify
f(x) = 3x - 3
g(x) = 3x³ + 5
f(-3) is x = -3 for function f(x)
g(-2) is x = -2 for function g(x)
Step 2: Evaluate
f(-3)
- Substitute in x [Function f(x)]: f(-3) = 3(-3) - 3
- Multiply: f(-3) = -9 - 3
- Subtract: f(-3) = -12
g(-2)
- Substitute in x [Function g(x)]: g(-2) = 3(-2)³ + 5
- Exponents: g(-2) = 3(-8) + 5
- Multiply: g(-2) = -24 + 5
- Add: g(-2) = -19
Answer:
f(-3) = -12
g(-2) = -19
Step-by-step explanation:
1.
f(x) = 3x - 3
One is asked to find (f(-3)), substitute (-3) into the given function (f) in place of (-3), and solve to evaluate,
f(-3) = 3(-3) - 3
Simplify,
= -9 - 3
= -12
2.
g(x) = [tex]3x^3+5[/tex]
The problem asks one to find (g(-2)), subtitute (-2) into the function in place of (x) and solve to find tis value,
g(-2) = [tex]3(-2)^3+5\\[/tex]
Remember any number raised to an exponent is equal to the base (the number that is being raised to the exponent) times itself the number of times that the exponent indicates,
[tex]=3(-8)+5\\=-24+5\\=-19[/tex]