Answer:
[tex]\text{d. }106,250\:\mathrm{cm^2},\\\text{e. }38.5\:\mathrm{cm^2},\\\text{a. }85\:\mathrm{ft^2},\\\text{b. }7.89676\:\mathrm{m^2}[/tex]
Step-by-step explanation:
Part D:
The figure shows a parallelogram with base 425 cm and height 250 cm. Its area can be found by [tex]A=bh[/tex] and therefore the area of this shape is [tex]A=425\cdot 250=\boxed{106,250\:\mathrm{cm^2}}[/tex]
Part E:
The figure shows a trapezoid. The area of a trapezoid is equal to the average of its bases multiplied by the height. Since one base is 2 cm and the other base is 9 cm, the average of these bases is [tex]\frac{2+9}{2}=\frac{11}{2}=5.5\:\mathrm{cm}[/tex]. The height is given as 7 cm, therefore the area of the trapezoid is [tex]7\cdot 5.5=\boxed{38.5\:\mathrm{cm^2}}[/tex]
Part A:
The composite figure consists of two rectangles. The area of a rectangle with base [tex]b[/tex] and height [tex]h[/tex] is given by [tex]A=bh[/tex]. The total area of the figure is equal to the sum of the areas of these two rectangles.
Area of first rectangle (rectangle on bottom): [tex]5\cdot 13=65\:\mathrm{ft^2}[/tex]
Area of second rectangle (rectangle on top):
*Since we don't know the dimensions, we must find them. Start by converting 108 inches to feet:
[tex]108\:\mathrm{in}=9\:\mathrm{ft}[/tex]. Therefore, the dimensions of this rectangle are (10-5) ft by (13-9) ft [tex]\implies5\text{ by } 4[/tex] and this rectangle's area is [tex]5\cdot 4=20\:\mathrm{ft^2}[/tex]
Thus, the area of the figure is equal to [tex]65+20=\boxed{85\:\mathrm{ft^2}}[/tex]
Part B:
We've already found the area of the figure in the previous part in square feet. To find the area in square meters, use the conversion [tex]1\text{ square foot}=0.092903\text{ square meter}[/tex].
Therefore, the area of the figure, in square meters, is [tex]85\cdot 0.092903=\boxed{7.89676\:\mathrm{m^2}}[/tex]
