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We need 50 ml of a 12% alcohol solution.
We have 10% and 15% alcohol solutions and we want 50 ml at 12%
We set up 2 equations (x is volume of 10% y is volume of 15%)
a) x + y = 50
b) .1x + .15y = 6.0 (which is 50 ml at 12% or .12 * 50)
multiplying equation "a" by -.1 then add it to "b"
a) -.1x -.1y = -5
b) .1x +.15y = 6.0
.05y = 1
y = 20 ml of 15% and therefore x would equal 30 ml of 10%
We need 50 ml of a 12% alcohol solution.
We have 10% and 15% alcohol solutions and we want 50 ml at 12%
We set up 2 equations (x is volume of 10% y is volume of 15%)
a) x + y = 50
b) .1x + .15y = 6.0 (which is 50 ml at 12% or .12 * 50)
multiplying equation "a" by -.1 then add it to "b"
a) -.1x -.1y = -5
b) .1x +.15y = 6.0
.05y = 1
y = 20 ml of 15% and therefore x would equal 30 ml of 10%
Answer:
0.10x + 0.15(50 – x) = 0.12(50)
Step-by-step explanation: