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Which compound inequality is equivalent to | ax -b | > C for all real numbers a, b, and c, where c>0?

Which compound inequality is equivalent to ax b gt C for all real numbers a b and c where cgt0 class=

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caylus

Hello,

Answer D

ax-b < -c or ax-b >c

If ax-b >0 then |ax-b| = ax-b ==> ax-b > c

if ax-b <0 then |ax-b|=-(ax-b) > c ==> ax-b <-c

The equivalent compoud inequality is (d) ax - b > c or ax - b < -c

How to determine the  compound inequality?

The absolute value expression is given as:

| ax -b | > c

Given that c > 0, then it means that:

| ax -b | > 0

So, we have the following inequalities from | ax -b | > c

  1. ax - b > c
  2. ax - b < -c

Hence, the equivalent compoud inequality is (d) ax - b > c or ax - b < -c

Read more about compoud inequality at:

https://brainly.com/question/24544713