Answer:
the sum is 3m-12
Step-by-step explanation:
The nunbers are:
[tex]m-2\\m-4\\m-6\\the~sum~is:\\sum=(m-2)+(m-4)+(m-6)\\sum=m-2+m-4+m-6=m+m+m-2-4-6\\sum=3m-12[/tex]
The sum of three odd consecutive integers is 3m - 12
"These are the integers which are not divisible by 2."
For given question,
We need to find the sum of three consecutive odd integers.
Let x, x + 2, x + 4 be three consecutive odd integers.
We have been given the last one is m - 2
This means x + 4 = m - 2
So, the second odd integer would be,
x + 2 = m - 4
and the first odd integer would be,
x = m - 6
, we find the sum of the three odd consecutive integers.
⇒ (m - 6) + (m - 4) + (m - 2)
= m + m + m - 6 - 4 - 2
= 3m - (6 + 4 + 2)
= 3m - 12
Therefore, the sum of three odd consecutive integers is 3m - 12
Learn more about the odd integers here:
https://brainly.com/question/18365251
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