Respuesta :

rvillalta2002

Answer:

there are two solutions:

x=0

and

x=14

Step-by-step explanation:

lts suppose the numbers are x and x+2, so:

[tex]x(x+2)=8(x+(x+2))-16\\x(x+2)=8(2x+2)-16=16x+16-16=16x\\x^2+2x=16x\\x^2-14x=0\\x(x-14)=0\\x=0,~x=14[/tex]

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