the vertex of the parabola is calculated by the formula
[tex]\displaystyle\ ax^2+bx+c\quad ;\quad \boxed{x_0=\frac{-b}{2a} \ \ ;\quad y_0 =ax_0^2+bx_0+c} \\\\x_0=-\frac{-8}{2} =4 \quad ; \ \ y_0 =16-32-9=-25 \\\\\ \ Answer: Coordinates \ \ of \ the \ vertex \ of \ the \ \ parabola \ \ (4;-25)[/tex]
