Respuesta :

(not a or not b) implies c   <==>   not (not a or not b) or c

so negating gives

not [(not a or not b) implies c]   <==>   not[ not (not a or not b) or c]

which we can simplify somewhat to

not (not (not a or not b)) and not c

(not a or not b) and not c

(not a and not c) or (not b and not c)

not (a or c) or not (b or c)

not ((a or c) and (b or c))

not ((a and b) or c)