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A marble is rolling across a smooth 1.2 m tall table at a velocity of 3 m/s. How far from the edge of the table does it land? (SHOW ALL OF YOUR WORK)

Respuesta :

Answer:

S = 1/2 g t^2      where t is the time to fall 1.2 m

t = (2 S / g)^1/2 = (2 * 1.2 / 9.8) = .495 s

Sy = Vy T = 3 m/sec  * .495  sec = 1.48 m     distance from edge of table

(Rotational speed has no effect since table is smooth)

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