Answer:
R = 0.86 m
Explanation:
The formula for the range of the projectile motion can be used here:
[tex]R = \frac{v^2 Sin2\theta}{g}[/tex]
where,
R = Range of projectile = distance between Jake and Fred = ?
v = launch speed = 3 m/s
θ = Launch Angle = 35°
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]R = \frac{(3\ m/s)^2Sin[(2)(35^o)]}{9.81\ m/s^2}\\\\[/tex]
R = 0.86 m
