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Find the probability of rolling a three first and then a six when a pair of dice is rolled twice.


a. 1/18

b. 5/648

c. 1/54

d. 5/324

Plz help me

Respuesta :

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Answer:

5 / 648

Step-by-step explanation:

Given tbe sample space for a pair of dice attached below :

Sample space for a pair of dice = 6² = 36

Rolling a 3 first :

Recall, probability = required outcome / Total possible outcomes

P(rolling a 3). = 2 / 36 = 1 /18

Probability of rolling a 6 (second roll)

P(rolling a 6) = 5 / 36

Hence,

P(3) then P(6) ;

1 / 18 * 5/36 = 5 / 648

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