Answer:
0.037
Step-by-step explanation:
Given that,
Let a and b be the solutions to [tex]x^2 + x -3 = 0[/tex]
It can be solved using quadratic formula where a = 1, b = 1 and c = -3
So,
[tex]x=\dfrac{-1+\sqrt{1^2-4\times 1\times (-3)}}{2(1)},\dfrac{-1-\sqrt{1^2-4\times 1\times (-3)}}{2(1)}\\\\x=1.30,-2.3[/tex]
Let a = 1.3, b = -2.3
The value of [tex]a^3 -4b^2 + 19[/tex] can be given by :
[tex]a^3 -4b^2 + 19=(1.3)^3-4\times (-2.3)^2+19\\\\=0.037[/tex]
So, the value of the given expression is 0.037.
