Answer:
4/3
Step-by-step explanation:
In slope-intercept form [tex]y=mx+b[/tex], [tex]m[/tex] represents the slope of the line.
Let's write [tex]3x+4y=-2[/tex] in slope-intercept form by isolating [tex]y[/tex]:
[tex]3x+4y=-2,\\4y=-3x-2,\\y=-\frac{3}{4}x-\frac{1}{2}[/tex]
Therefore, the slope of this line is [tex]\frac{-3}{4}[/tex]. To find the slope of a line perpendicular to it, multiply the reciprocal of the slope by -1 (take the negative reciprocal).
Therefore, the slope of a line perpendicular to [tex]3x+4y=-2[/tex] is:
[tex]m_{perp}=-(-\frac{4}{3})=\boxed{\frac{4}{3}}[/tex]
