The function has the characteristics is (b) y= (2x^2 - 8) / (x^2 - 9)
How to determine the function?
The features are given as:
- A vertical asymptote at x=3
- A horizontal asymptote at y=2
- Domain: {x ≠ ±3}
The function that has the above features is (b).
This is proved as follows:
y= (2x^2 - 8) / (x^2 - 9)
Set the denominator not equal to 0, to determine the domain
x^2 - 9 ≠ 0
Add 9 to both sides
x^2 ≠ 9
Take the square roots
x ≠ ±3 --- domain
Replace ≠ with =
x = ±3 --- vertical asymptote
Set the numerator to 0
2x^2 - 8 = 0
Divide through by 2
x^2 - 4 = 0
This gives
x^2 = 4
Take the square roots
x = 2 ---- horizontal asymptote
Hence, the function has the characteristics is (b) y= (2x^2 - 8) / (x^2 - 9)
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