Respuesta :
Answer:
281 different committees can be formed if the number of boys is more than the number of girls.
Step-by-step explanation:
The order in which the people are chosen to the committee is not important, which means that the combinations formula is used to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Number of boys more than the number of girls:
3, 4 or 5 boys.
3 boys:
3 boys from a set of 6.
2 girls from a set of 5. So
[tex]C_{6,3}C_{5,2} = \frac{6!}{3!3!} \times \frac{5!}{2!3!} = 200[/tex]
4 boys:
4 boys from a set of 6.
1 girl from a set of 5. So
[tex]C_{6,4}C_{5,1} = \frac{6!}{4!2!} \times \frac{5!}{1!4!} = 75[/tex]
5 boys:
5 boys from a set of 6. So
[tex]C_{6,5} = \frac{6!}{5!1!} = 6[/tex]
Total:
200 + 75 + 6 = 281
281 different committees can be formed if the number of boys is more than the number of girls.
