Answer:
[tex]\frac{AB}{BC} = \frac{CE}{ED}[/tex]
Step-by-step explanation:
Given
The attached proof
Required
Complete the missing piece
In (a), we have:
[tex]\triangle ABC \to \triangle CED[/tex]
This implies that, the following sides are similar:
[tex]AB \to CE[/tex]
[tex]AC \to CD[/tex]
[tex]BC \to ED[/tex]
An equation that compares the triangle can be any of:
[tex]\frac{AB}{BC} = \frac{CE}{ED}[/tex]
[tex]\frac{AB}{AC} = \frac{CE}{CD}[/tex]
.....
From the options;
[tex]\frac{AB}{BC} = \frac{CE}{ED}[/tex] is true
