[tex] {\bold{\red{\huge{\mathbb{QUESTION}}}}} [/tex]
The lengths of the sides of a triangle are 3, 3, 3√2. Can the triangle be a right triangle?
[tex]\bold{ \red{\star{\blue{TO \: \: PROVE }}}}[/tex]
IF ITS A RIGHT ANGLED OR NOT
[tex]\bold{\blue{\star{\red{FORMULA}}}}[/tex]
IF IT WILL FOLLOW PYTHAGORAS THEOREM THEN IT WILL BE A RIGHT ANGLE TRIANGLE.
[tex]{HYPOTENUSE}^{2} \\ ={ PERPENDICULAR}^{2}+{BASE}^{2} [/tex]
[tex]\bold{ \red{\star{\orange{GIVEN }}}}[/tex]
1ST SIDE -> 3
2ND SIDE -> 3
3RD SIDE ->3√2
[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]
[tex]{HYPOTENUSE}^{2}\\ ={ PERPENDICULAR}^{2}+{BASE}^{2} \\{h}^{2}={p}^{2}+{b}^{2} [/tex]
AS HYPOTENUSE is always greater than other 2 sides so 3√2 can only be hypotenuse if it's a right angle triangle
[tex]{(3 \sqrt{2})}^{2} = {3}^{2} + {3}^{2} \\ 9 \times2 = 9 + 9 \\ 18 = 18[/tex]
[tex] {\red{\star}}{ \blue{HENCE \: PROVED}} { \red{ \star}}[/tex]
[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]
