HELP PLS!!

Find the value of x and the value of y.
A. x = 16, y = 9√2
B. X= 7, y = 16√2
C. x = 6√2, y=7√2
D. X= 7√3, y = 16

HELP PLS Find the value of x and the value of y A x 16 y 92 B X 7 y 162 C x 62 y72 D X 73 y 16 class=

Respuesta :

Answer:

A

Step-by-step explanation:

Thanks to the given angle, we can say that the triangle formed by tracing another height has two congruent legs

So

x = 9 + 7 = 16

y = √2 * 9^2 = 9√2

Answer:

A

Step-by-step explanation:

Completing the rectangle formed by legs 9 and 7 , gives us a right triangle on the left.

Using the sine ratio and the exact value sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then

sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{9}{y}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )

y = 9[tex]\sqrt{2}[/tex]

Using the tan ratio in the right triangle and the value tan45° = 1 , then

tan45° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{9}{adj}[/tex] = 1

adj = 9

Then

x = 9 + 7 = 16