Respuesta :
Answer:
It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)
Step-by-step explanation:
[tex] {n}^{2} - 2 - ( {n}^{2} + 4 - 4n) = \\ {n}^{2} - 2 - {n}^{2} - 4 + 4n = \\ 4n - 6 = 2(2n - 3)[/tex]
Answer:
It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)
Step-by-step explanation:
[tex] {n}^{2} - 2 - ( {n}^{2} + 4 - 4n) = \\ {n}^{2} - 2 - {n}^{2} - 4 + 4n = \\ 4n - 6 = 2(2n - 3)[/tex]