9514 1404 393
Answer:
16. k^5/j^3
18. 81y^20
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c) . . . . where b may be 0
(a^b)^c = a^(bc)
(ab)^c = (a^c)(b^c)
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We can simplify the given expressions as follows.
16.
[tex]\dfrac{k^6j^2}{kj^5}=k^{6-1}j^{2-5}=k^5j^{-3}=\boxed{\dfrac{k^5}{j^3}}[/tex]
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18.
[tex](x^{-2})^2(3xy^5)^4=(x^{-2\cdot2})(3^4x^4y^{5\cdot4})=81x^{-4+4}y^{20}=\boxed{81y^{20}}[/tex]
