Given:
The inequalities are:
[tex]y>\dfrac{2}{3}x+3[/tex]
[tex]y\leq -\dfrac{1}{3}x+2[/tex]
To find:
The graph for the given system of inequities.
Solution:
We have,
[tex]y>\dfrac{2}{3}x+3[/tex]
[tex]y\leq -\dfrac{1}{3}x+2[/tex]
The related equations are:
[tex]y=\dfrac{2}{3}x+3[/tex]
[tex]y=-\dfrac{1}{3}x+2[/tex]
Table of values
x [tex]y=\dfrac{2}{3}x+3[/tex] [tex]y=-\dfrac{1}{3}x+2[/tex]
0 3 2
3 5 1
Plot the points (0,3) and (3,5) and connect them by a straight line to get the boundary line [tex]y=\dfrac{2}{3}x+3[/tex].
Plot the points (0,2) and (3,1) and connect them by a straight line to get the boundary line [tex]y=-\dfrac{1}{3}x+2[/tex].
In [tex]y>\dfrac{2}{3}x+3[/tex], the sign of inequality is ">" it means the boundary line is a dashed line and shaded area lies above the boundary line.
[tex]y\leq -\dfrac{1}{3}x+2[/tex], the sign of inequality is "[tex]\leq [/tex]" it means the boundary line is a solid line and shaded area lies below the boundary line.
Therefore, the required graph is shown below.
