Answer:
Explanation:
Given that:
The scaling of the specific metabolic rate is:
[tex]=\dfrac{P_{metab}}{m}[/tex]
where;
[tex]P_{metab} = 70M_b^{0.75}[/tex]
[tex]=\dfrac{ 70M_b^{0.75}}{m}[/tex]
(a) For a mouse whose mass = 30 g = 0.030 kg
The specific metabolic rate [tex]=\dfrac{ 70*(0.030)^{0.75}}{(0.030)}[/tex]
= 168.197 kg
≅ 168 kg to 3 significant fig.
(a) For a cow whose mass = 300 kg
The specific metabolic rate [tex]=\dfrac{ 70*(300)^{0.75}}{(300)}[/tex]
= 16.8197 kg
≅ 16.8 kg to 3 significant fig.
