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A gas sample has a volume of 4250 mL at 15 degree Celsius and 745 mmHg. What is the final temperature, in degree Celsius, after the sample is transferred to a different container with a volume of 2.50 L and a pressure of 1.20 atm if the amount of gas does not change?

Respuesta :

Answer:

[tex]T_f=-66^0C[/tex]

Explanation:

Given;

volume=4250 mL at 15 degree C and 745 mm Hg

Formula used:

PV=nRt

[tex]n=\frac{P_iV_i}{R_iT_i}[/tex]

Solution:

[tex]P_i=745 mm Hg=\frac{745}{760}atm\\PV=nRt\\n=\frac{P_iV_i}{R_iT_i}\\ =\frac{745*4.250}{760*0.032*288} \\[/tex]

After transfer of ags moles of gas will remain same

[tex]n=\frac{P_fV_f}{RT_f}\\\frac{745*4.250}{760*0.082*283}=\frac{1.2*2.50}{0.082*T-f}\\T_f=\frac{1.2*2.50*760*283}{745*4.250}\\T_f=207.38 K\\T_f=-66^0 C[/tex]

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