Answer:
21.9% is the experimental percentage of water in the unknown hydrate.
Explanation:
The mass of an unknown hydrate = 1.000 g
The mass of hydrate after heating = 0.781 g
The mass of water lost due to heating = x
[tex]1.000 g = 0.781 g + x\\x = 1.000 g - 0.781 g = 0.219 g[/tex]
The experimental percentage of water in the unknown hydrate:
[tex]Water(\%)=\frac{\text{Mass of water lost after heating}}{\text{Mass of hydrate before heating}}\times 100\\Water(\%)=\frac{0.219 g}{1.000 g}\times 100\\=21.9\%[/tex]
21.9% is the experimental percentage of water in the unknown hydrate.
