Respuesta :
Answer: The mass of carbon monoxide required is 1.094 kg
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of iron (III) oxide = 2.08 kg = 2080 g (Conversion factor: 1 kg = 1000 g)
Molar mass of iron (III) oxide = 159.69 g/mol
Plugging values in equation 1:
[tex]\text{Moles of iron (III) oxide}=\frac{2080g}{159.69g/mol}=13.02 mol[/tex]
The given chemical equation follows:
[tex]Fe_2O_3+3CO\rightarrow 2Fe+3CO_2[/tex]
By the stoichiometry of the reaction:
If 1 mole of iron (III) oxide reacts with 3 moles of CO
So, 13.02 moles of iron (III) oxide will react with = [tex]\frac{3}{1}\times 13.02=39.06mol[/tex] of CO
Molar mass of CO = 28.01 g/mol
Plugging values in equation 1:
[tex]\text{Mass of carbon monoxide}=(39.06mol\times 28.01g/mol)=1094.07g=1.094kg[/tex]
Hence, the mass of carbon monoxide required is 1.094 kg
