Of the four choices given, which two, when written as a system, have a solution of (-4,5)?
х
-1
2
3
5
y
2
-1
-2
-4
2x+y=-3
-2x+y=-3
Х
-1
2.
3
7
0
-3
4
-8
2x+y=-3 and
Х
--1
2
3
5
y
2.
-1
-2
-4
0-2x+y=-3 and
х
-1
2
3
5
у
2.
-1
-2
-4

Of the four choices given which two when written as a system have a solution of 45 х 1 2 3 5 y 2 1 2 4 2xy3 2xy3 Х 1 2 3 7 0 3 4 8 2xy3 and Х 1 2 3 5 y 2 1 2 4 class=

Respuesta :

Answer:

both choices with 2x+y = -3

Step-by-step explanation:

to have the solution (-4, 5), that point must be on both equations/functions, meaning it must be on either one.

in other words, if the point is not on at least one of the functions, it cannot be a solution for that system.

the given function

2x + y = -3

looks like for the point (-4, 5)

2×-4 + 5 = -3

-8 + 5 = -3

-3 = -3

correct.

but

-2x + y = -3

looks like for (-4, 5)

-2×-4 + 5 = -3

8 + 5 = -3

13 = -3

wrong. the point is not on this function.

as we can therefore rule out 2 of the answer options, the other 2 most be correct.

The two equations which when written as a system has a solution of (-4, 5) is; 2x + y = -3 and 2x + y = -3

Inequalities

The correct equations must have same output with the given one when we place -4 and 5 for x and y respectively.

Now, for 2x + y = -3

At x = -4, and y = 5 we have;

2(-4) + 5 = -3

Same with the right hand side.

For -2x + y = -3;

At x = -4, and y = 5 we have;

-2(-4) + 5 = 13

Not the same with the right hand side.

Thus, the two equations with 2x + y = -3 are correct

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