It can be concluded that "segment BC ~ segment EF because corresponding parts of similar triangles are proportional
". option D is correct.
Given information:
Triangles ABC and FDE, in which angles A and D are right angles.
∠F is congruent to ∠C.
From the given information, in triangles ABC and FDE,
[tex]\angle A=\angle D=90^{\circ}\\\angle F=\angle C[/tex]
So, by Angle-angle (AA) similarity rule, the two triangles will be similar.
So, [tex]\Delta ABC \sim \Delta DFE[/tex]
Now, the triangles are similar. So, the ratio of their sides will be in the same ratio. It can be written as,
[tex]\dfrac{AB}{DF}=\dfrac{BC}{FE}=\dfrac{AC}{DE}[/tex]
Therefore, it can be concluded that "segment BC ~ segment EF because corresponding parts of similar triangles are proportional
".
For more details, refer to the link:
https://brainly.com/question/19738610