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A piece of wire that is 200 ft long is to be cut into two pieces and each of the piece is to be bent into a square. How should the wire be cut if the area of one of the squares is 1000ft2 smaller than the other?

A piece of wire that is 200 ft long is to be cut into two pieces and each of the piece is to be bent into a square How should the wire be cut if the area of one class=

Respuesta :

Answer:

Length of first cut = 140

Length of second cut = 60

Step-by-step explanation:

Given:

Length of wire = 200

Find:

Length of each cut

Computation:

Assume;

Side of first square = x/4

Side of second square = [200 - x] / 4 = 50 - x/4

So,

[x/4]² - [50 - x/4]²

x²/16 - x²/16 - 2500 + 25x = 1000

- 2500 + 25x = 1000

25x = 3500

x = 140

Side of first square = 140/4

Side of first square = 35

Side of second square = 50 - 140/4

Side of second square = 15

Length of first cut = 4 x 35

Length of first cut = 140

Length of second cut = 200 - 140

Length of second cut = 60

Numenius

Answer:

60 ft and 140 ft

Step-by-step explanation:

Total length = 200 ft

Let the length of one piece is L and other is 200 - L.

[tex]1000 + \left (\frac{L}{4} \right )^2 = \left ( \frac{200 - L}{4} \right )^2\\\\16000 +L^2 = 40000 + L^2 - 400 L\\\\L= 60 ft[/tex]

So, the length of the other piece is 140 ft.

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