Hello,
[tex](x-4)^2-\dfrac{2}{3} =6y-12\\\\Permuting\ x\ and\ y\ gives:\\\\(y-4)^2-\dfrac{2}{3} =6x-12\\\\\\(y-4)^2=6x-12-\dfrac{2}{3} \\\\(y-4)^2=6x-\dfrac{34}{3} \\\\y-4=\pm \sqrt{6x-\dfrac{34}{3}}\\y=4\pm \sqrt{6x-\dfrac{34}{3}}\\[/tex]
But this expression is not a function you must write it in 2 forms uisng an union.
