Isosceles trapezoid EFGH has area 80 cm ^2, height 20 cm and legs 22 cm. One of the bases is 5 cm. How long is the remaining base ?

Answer:
3
Step-by-step explanation:
A = [tex]\frac{base1 + base2}{2}[/tex] x h Formula
[tex]\frac{base1 + 5}{2}[/tex] x 20 = 80 Substitution
[tex]\frac{base1 + 5}{2}[/tex] = 4 Work (divide by 20, multiply by 2, subtract 5)
base1 + 5 = 8
base1 = 3 Solution