Find the area of the triangle with vertices A(-3,2), B(1,-2), and c(1,3)

Answer:
[tex]A(-3,2)\: B(-1,-2)\: C(1,3)[/tex]
[tex]A=1/2[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)][/tex]
[tex]=1/2[-3(-2-3)(+1(3-2)+1(2-(-2))][/tex]
[tex]=1/2(15+1+4)[/tex]
[tex]=1/2(20)[/tex]
[tex]=10[/tex]
[tex]ANSWER: 10 ~units^{2}[/tex]
------------------------------
hope it helps...
have a great day!!
The area of triangle with vertices A(-3,2), B(1,-2), and c(1,3) is 12 units^2.
The area of a triangle is defined as the total space occupied by the three sides of a triangle in a 2-dimensional plane. The basic formula for the area of a triangle is equal to half the product of its base and height, i.e., A = 1/2 × b × h.
The green line represents the height of the triangle = 4 units
The red line represents the base of the triangle = 6 units
Area of the triangle = 1/2 x 6 x 4 = 12 units^2
Learn more about area of triangle here
https://brainly.com/question/19305981
#SPJ2