Given:
The sum of two numbers is 24 and their difference is one sixth of the sum.
To find:
The smaller number between the two numbers.
Solution:
Let x and y be the two numbers where x>y.
The sum of two numbers is 24.
[tex]x+y=24[/tex] ...(i)
Their difference is one sixth of the sum.
[tex]x-y=\dfrac{1}{6}\times 24[/tex]
[tex]x-y=4[/tex] ...(ii)
Adding (i) and (ii), we get
[tex]2x=28[/tex]
[tex]x=\dfrac{28}{2}[/tex]
[tex]x=14[/tex]
Putting [tex]x=14[/tex] in (i), we get
[tex]14+y=24[/tex]
[tex]y=24-14[/tex]
[tex]y=10[/tex]
The two numbers are 14 and 10.
Therefore, the smaller number between the two numbers is 10.
