Answer:
a: t=13.6 cm
b: h=12.9 mm
Step-by-step explanation:
Hi there!
Let's start with a
in a, we are given a right triangle (notice the right angle), the length of the hypotenuse (the side OPPOSITE from the right angle) as 18 cm, one acute angle given as 41° and the length of one of the legs (the legs are the sides that make up the right angle) as t
We're asked to use the primary trigonometric ratios
Those ratios are:
Sine, which is opposite/hypotenuse
Cosine, which is adjacent/hypotenuse
Tangent, which is opposite/adjacent
We will be basing the ratio off of the 41° angle, so let's find out which sides will be which in reference to that angle
The opposite side will be the other leg, the unmarked side
The adjacent side will be t
The hypotenuse will be the side marked as 18 cm
So let's use cos(41) in this case
cos(41)=t/18
Plug cos(41) into your calculator, and remember to have the calculator in degree mode
cos(41)≈0.8 (rounded to the nearest tenth)
0.8=t/18
multiply both sides by 18
13.6 cm=t
It's already rounded to the nearest tenth :)
b.
We are given a right triangle, and the lengths of the legs as h and 9 mm, as well as one acute angle as 35°
We'll be basing our ratio off of the 35 degree angle, so let's find which sides will be which in reference to that angle
The opposite side will be the leg marked as 9 mm
The adjacent side will be the leg marked as h
The hypotenuse will be the unmarked side
Since we are given the lengths of the opposite and the adjacent, let's use tan(35)
tan(35)=9/h
Plug tan(35) into your calculator, and remember to have it in degree mode
tan(35)≈0.7
0.7=9/h
multiply both sides by h
0.7h=9
divide both sides by 0.7
h=12.9 mm (rounded to the nearest tenth)
Hope this helps!
